Lesson 6

Problem Solving with Area

Est. Class Sessions: 1–2

Daily Practice and Problems

Teacher Notes
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TIMS Challenge

DPP Challenge V can be used as a Problem of the Week.

  1. Each square has an area of 16 square units, so the total figure has an area of 48 square units. In this figure one full square is shaded and one full square is not shaded. The third square is cut in half diagonally. That means 8 square units are shaded and 8 square units are not shaded. The total area of the shaded part is 24 square units and the non-shaded part is 24 square units.
    1. 16 square units
    2. 24 square units
    3. I know that the whole shaded square has an area of 16 square units. To find the area of the shaded part of the top square I drew a rectangle around the triangle. The rectangle has an area of 4 square units and the shaded part is 1/2 that or 2 square units. Then I did the same thing on the bottom. The rectangle has an area of 12 square units so 1/2 will be 6 square units. Then I added 16 + 2 + 6 = 24 square units.

V. Problem Solve with Area

  1. This shape is made of 3 big squares. Show or tell how you know the area of the shaded part is equal to the area of the part that is not shaded.
  2. Find the area of the shaded part of each figure.
    3. Show or tell the strategy you used to find the area in Question B.