Lesson 2

Using Common Denominators

Est. Class Sessions: 2–3

Daily Practice and Problems

Teacher Notes
X

TIMS Task

    1. 106
    2. 249 R2
    3. 3736
    4. 162.26
    5. 11,705
    6. 1125
  2. Possible response:
    1600 ÷ 8 = 200
    2400 ÷ 8 = 300
    So the answer is between 200 and 300. 249 R2 is reasonable.
  3. Possible response for Question 1F: 125 × 10 = 1250
    1250 − 125 = 1125

H. Operations

Choose a strategy to solve each problem. Use any pages in the Student Guide Reference section.

    1. 636 ÷ 6 =
    2. 1994 ÷ 8 =
    3. 467 × 8 =
    4. 37.2 + 125.06 =
    5. 2341 × 5 =
    6. 125 × 9 =
  2. Explain your estimation strategy for Question 1B.
  3. Choose a problem from Question 1 and show or tell how to solve it using mental math or a few quick notes.