Lesson 5

Life Spans

Est. Class Sessions: 1–2

Daily Practice and Problems

Teacher Notes
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TIMS Challenge

DPP Challenge N can be used as a Problem of the Week.

    1. $190.00
    2. $95.00; Possible response: I used division. I divided $570.00 by 6 to find the cost of one night.
    1. 3 miles
    2. 1.5 miles
    1. 17 adults
    2. $323.00:
      Possible response: To find the cost for each child I multiplied $2.00 × 136 = $272.00.
      The cost for the adults will be $3.00 × 17 = $51.00. Then I added $272.00 + $51.00 = $323.00.
  1. $5260.00;
    Possible response: I divided $1315 by $5.00 equals 263. This means they collected $20.00 × 263 = $5260.00 total dollars.

N. Problem Solving

Choose a strategy to solve each problem. Use the pages in the Student Guide Reference section.

    1. A hotel charges $570.00 for a 6-night stay. How much is a 2-night stay?
    2. How much does the hotel charge per night? How did you decide?
    1. Jessie can walk half a mile in 10 minutes. How far can she walk in an hour?
    2. If Jessie walks at this pace for a half hour, how far will she walk?
    1. For every eight children on a field trip there needs to be one adult chaperone. If there are 136 students going on the trip, how many chaperones are needed?
    2. The cost of the field trip is $2.00 per student and $3.00 per adult. How much money will this field trip cost? Show or tell how you solved this problem.
  1. For every $20.00 the students collect in school fundraisers, $5.00 goes toward decorating the cafeteria. If $1315 went toward the decorating project, how much money was collected in all? Explain the strategy you used to solve this problem.